Question 57 of 71
Q.If the temperature and pressure of a gas is doubled, the mean free path of the gas molecules :
(a) tripled
(b) remains same
(c) quadrupled
(d) doubled
Puducherry TnboardTamil Nadu HSC First Year (DGE) Board 2023MCQ· 1mImportance★★★★★
80% · 57/71 Questions
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Start your 14-day free trial to unlock the full solution →Mean free path lambda is proportional to T/P, so doubling both temperature and pressure leaves lambda unchanged.
The mean free path of gas molecules is given by
lambda = kT / (sqrt(2) pi d^2 P)
where k is Boltzmann's constant, d is the molecular diameter, T is the absolute temperature and P is the pressure.
This shows lambda is proportional to T/P, since k and d are constants for a given gas.
If both T and P are doubled: …
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