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Exercise 8.6 · Q9

Q.W(x,y,z)=xy+yz+zx, x=u−v, y=uv, z=u+v, u,v∈RW(x,y,z)=xy+yz+zx,\ x=u-v,\ y=uv,\ z=u+v,\ u,v\in\mathbb R. Find ∂W∂u,∂W∂v\dfrac{\partial W}{\partial u},\dfrac{\partial W}{\partial v}, and evaluate them at (12,1)\left(\dfrac12,1\right).

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Apply the two-parameter chain rule to W=xy+yz+zxW=xy+yz+zx with x=u−v, y=uv, z=u+vx=u-v,\,y=uv,\,z=u+v, then substitute (u,v)=(12,1)(u,v)=(\tfrac12,1).

Step 1. Partial derivatives of W=xy+yz+zxW=xy+yz+zx. Wx=y+zW_x=y+z. Wy=x+z\quad W_y=x+z. Wz=y+x\quad W_z=y+x.

Step 2. Partial derivatives of x=u−v, y=uv, z=u+vx=u-v,\,y=uv,\,z=u+v.

∂x∂u=1, ∂x∂v=−1\dfrac{\partial x}{\partial u}=1,\ \dfrac{\partial x}{\partial v}=-1. ∂y∂u=v, ∂y∂v=u\quad \dfrac{\partial y}{\partial u}=v,\ \dfrac{\partial y}{\partial v}=u. ∂z∂u=1, ∂z∂v=1\quad \dfrac{\partial z}{\partial u}=1,\ \dfrac{\partial z}{\partial v}=1.

Step 3. Evaluate x,y,zx,y,z at (u,v)=(12,1)(u,v)=\left(\dfrac12,1\right). x=12−1=−12x=\dfrac12-1=-\dfrac12.  y=12(1)=12\ y=\dfrac12(1)=\dfrac12.  z=12+1=32\ z=\dfrac12+1=\dfrac32.

So y+z=12+32=2y+z=\dfrac12+\dfrac32=2,  x+z=−12+32=1\ x+z=-\dfrac12+\dfrac32=1,  x+y=−12+12=0\ x+y=-\dfrac12+\dfrac12=0.

Step 4. Compute ∂W/∂u\partial W/\partial u. …

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