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Question 53 of 88

Q.State and prove De-Morgan's theorems.

Puducherry TnboardTamil Nadu HSC (DGE) Board 2017Subjective· 5mImportance★★★★★
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De Morgan's two theorems relate the complement of OR/AND combinations to AND/OR combinations of the individual complements, proved by truth table and gate equivalence.

Statement

First theorem: The complement of the sum (OR) of two variables equals the product (AND) of their individual complements:

A+B‾=Aˉ⋅Bˉ\overline{A+B} = \bar{A}\cdot\bar{B}

Second theorem: The complement of the product (AND) of two variables equals the sum (OR) of their individual complements:

A⋅B‾=Aˉ+Bˉ\overline{A\cdot B} = \bar{A}+\bar{B}

Proof of the first theorem by truth table

AABBA+BA+BA+B‾\overline{A+B}Aˉ\bar{A}Bˉ\bar{B}Aˉ⋅Bˉ\bar{A}\cdot\bar{B}
0001111
0110100
1010010
1110000

The columns for A+B‾\overline{A+B} and Aˉ⋅Bˉ\bar{A}\cdot\bar{B} are identical for all four input combinations, so A+B‾=Aˉ⋅Bˉ\overline{A+B} = \bar{A}\cdot\bar{B} is proved. This theorem shows that a NOR gate (OR followed by NOT) is logically equivalent to a bubbled AND gate — an AND gate with both inputs inverted.

Proof of the second theorem by truth table

AABBA⋅BA\cdot BA⋅B‾\overline{A\cdot B}Aˉ\bar{A}Bˉ\bar{B}Aˉ+Bˉ\bar{A}+\bar{B}
0001111
0101101
1001011
1110000
…

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