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II. Short Answer Questions · Q28

Q.Give the expression for work done by the gas.

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Step 1. As a gas expands quasi-statically, pushing a piston outward by a small distance dxdx, the small work done is dW=F dxdW=F\,dx; since the force is F=PAF=PA and A dx=dVA\,dx=dV, this gives dW=P dVdW=P\,dV.

Step 2. For a finite volume change from ViV_i to VfV_f, the total work done is the integral of this small work: W=∫ViVfP dV.W=\int_{V_i}^{V_f}P\,dV. …

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