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IV. Exercises · Q8

Q.In an adiabatic expansion of air, the volume is increased by 4%. What is the percentage change in pressure? (For air, γ=1.4\gamma = 1.4.)

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Step 1. For an adiabatic process, PVγ=constantPV^\gamma=\text{constant}. Taking the logarithm and differentiating: ln⁡P+γln⁡V=constant\ln P+\gamma\ln V=\text{constant}, so dPP+γdVV=0\dfrac{dP}{P}+\gamma\dfrac{dV}{V}=0, giving dPP=−γdVV.\dfrac{dP}{P}=-\gamma\dfrac{dV}{V}.

Step 2. The fractional volume increase is given as dVV=+4%=0.04\dfrac{dV}{V}=+4\%=0.04, and γ=1.4\gamma=1.4 for air.

Step 3. Substituting: dPP=−1.4×0.04=−0.056=−5.6%.\dfrac{dP}{P}=-1.4\times0.04=-0.056=-5.6\%. …

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