Skip to content
IV. Exercises · Q13

Q.Suppose a person wants to increase the efficiency of a reversible heat engine that is operating between 100°C and 300°C. There are two ways to increase the efficiency:

(a) by decreasing the cold reservoir temperature from 100°C to 50°C and keeping the hot reservoir temperature constant, or
(b) by increasing the temperature of the hot reservoir from 300°C to 350°C and keeping the cold reservoir temperature constant. Which is the more suitable method?
Tamil Nadu DgeTextbookSubjectiveImportance★★★★★
41% · 52/126 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Step 1. Convert to kelvin: initial TH=300°C+273=573 KT_H=300°C+273=573\ \text{K}, TL=100°C+273=373 KT_L=100°C+273=373\ \text{K}. Initial efficiency: η0=1−373573≈1−0.651=0.349=34.9%.\eta_0=1-\dfrac{373}{573}\approx1-0.651=0.349=34.9\%.

Step 2. Method (a): lower TLT_L to 50°C = 323 K, keeping TH=573 KT_H=573\ \text{K}: ηa=1−323573≈1−0.564=0.436=43.6%.\eta_a=1-\dfrac{323}{573}\approx1-0.564=0.436=43.6\%.

Step 3. Method (b): raise THT_H to 350°C = 623 K, keeping TL=373 KT_L=373\ \text{K}: ηb=1−373623≈1−0.599=0.401=40.1%.\eta_b=1-\dfrac{373}{623}\approx1-0.599=0.401=40.1\%. …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.