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IV. Exercises · Q7

Q.Normal human body temperature is 98.6°F. During high fever, if the temperature increases to 104°F, what is the change in the peak wavelength emitted by our body? (Assume the human body is a black body.)

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Step 1. Convert 98.6°F to kelvin: T1=(98.6+459.67)/1.8=558.27/1.8≈310.15 KT_1=(98.6+459.67)/1.8=558.27/1.8\approx310.15\ \text{K} (i.e. 37°C, normal body temperature, as expected).

Step 2. Convert 104°F to kelvin: T2=(104+459.67)/1.8=563.67/1.8≈313.15 KT_2=(104+459.67)/1.8=563.67/1.8\approx313.15\ \text{K} (i.e. 40°C).

Step 3. Apply Wien's displacement law, λm=bT\lambda_m=\dfrac{b}{T}, with b=2.898×10−3 m Kb=2.898\times10^{-3}\ \text{m K}: at T1T_1, λmax,1=2.898×10−3310.15≈9.348×10−6 m=9348 nm.\lambda_{max,1}=\dfrac{2.898\times10^{-3}}{310.15}\approx9.348\times10^{-6}\ \text{m}=9348\ \text{nm}. …

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