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Physics · Ch 2 — Kinematics

Average Velocity

2.10.1

Average Velocity

For a particle confined to move along the xx-direction, average velocity is just the change in the xx-coordinate divided by the elapsed time:

vavg=ΔxΔt=x2−x1t2−t1v_{avg} = \frac{\Delta x}{\Delta t} = \frac{x_2-x_1}{t_2-t_1}

Average velocity remains a vector quantity even in one dimension, but with only two possible directions (positive xx or negative xx) along a line, a plain ++ or −- sign is enough to record direction — no separate arrow notation is needed.

The instantaneous velocity is, as before, the limit of this ratio as the time interval shrinks to zero:

v=lim⁡Δt→0ΔxΔt=dxdtv = \lim_{\Delta t\to0}\frac{\Delta x}{\Delta t} = \frac{dx}{dt}

Graphically, the slope of the position-time (xx-tt) graph at a point gives the velocity at that instant.

Going the other way — from a velocity-time graph back to displacement. Since v=dx/dtv=dx/dt, we can write dx=v dtdx = v\,dt, and integrating both sides between times t1t_1 and t2t_2,

∫x1x2dx=∫t1t2v dt⟹x2−x1=∫t1t2v dt\int_{x_1}^{x_2} dx = \int_{t_1}^{t_2} v\,dt \qquad\Longrightarrow\qquad x_2-x_1 = \int_{t_1}^{t_2} v\,dt …

Figure 2.35Displacement in the velocity-time graph

What this figure shows. A velocity-time graph with the curve dipping below the time axis in one stretch; the shaded area above the axis (between t1t_1 and where vv crosses zero) is labelled 'Positive displacement' and the shaded area below the axis is labelled 'Negative displacement', illustrating that the signed area under a vv-tt graph gives displa …