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I. Multiple Choice Questions · Q6

Q.Two wires A and B with circular cross section are made up of the same material with equal lengths. Suppose RA=3RBR_A = 3R_B, then what is the ratio of radius of wire A to that of B?

(a) 3
(b) 3\sqrt{3}
(c) 13\dfrac{1}{\sqrt{3}}
(d) 13\dfrac{1}{3}
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Step 1. For wires of the same material and equal length, R=ρl/AR=\rho l/A with ρ\rho and ll identical for both, so R∝1/AR\propto1/A.

Step 2. For a circular cross section, A=πr2A=\pi r^2, so R∝1/r2R\propto1/r^2.

Step 3. Given RA=3RBR_A=3R_B: since R∝1/r2R\propto1/r^2, RARB=rB2rA2=3\dfrac{R_A}{R_B}=\dfrac{r_B^2}{r_A^2}=3, so rA2rB2=13\dfrac{r_A^2}{r_B^2}=\dfrac13, giving rArB=13\dfrac{r_A}{r_B}=\dfrac{1}{\sqrt3}.

Step 4. This makes physical sense: wire A has the LARGER resistance, so it must be the THINNER wire (smaller radius), confirming rA/rB<1r_A/r_B<1. …

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