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IV. Numerical Problems · Q7

Q.An electronics hobbyist is building a radio which requires 150 Ω150\ \Omega in her circuit. But she has only 220 Ω220\ \Omega, 79 Ω79\ \Omega and 92 Ω92\ \Omega resistors available. How can she connect the available resistors to get the desired value of resistance?

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Step 1. The target is 150 Ω150\ \Omega from resistors of 220 Ω220\ \Omega, 79 Ω79\ \Omega and 92 Ω92\ \Omega.

Step 2. Try combining 220 Ω220\ \Omega and 79 Ω79\ \Omega in parallel: Rp=(220)(79)220+79=17380299≈58.1 ΩR_p=\dfrac{(220)(79)}{220+79}=\dfrac{17380}{299}\approx58.1\ \Omega.

Step 3. Adding the remaining 92 Ω92\ \Omega resistor in SERIES with this parallel pair gives Rtotal=58.1+92≈150.1 ΩR_{total}=58.1+92\approx150.1\ \Omega -- very close to the desired 150 Ω150\ \Omega. …

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