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IV. Numerical Problems · Q2

Q.Lightning is a very good example of natural current. In a typical lightning strike, there is 10910^9 J of energy transferred across a potential difference of 5×1075\times10^7 V during a time interval of 0.2 s. Using this information, estimate

(a) the total amount of charge transferred between the cloud and the ground,
(b) the current in the lightning bolt,
(c) the power delivered in the 0.2 s.
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✓ Free question

Step 1. Given: energy W=109W=10^9 J, potential difference V=5×107V=5\times10^7 V, time t=0.2t=0.2 s.

Step 2 (a). Since energy is charge times potential difference, W=QVW=QV, the charge transferred is Q=WV=1095×107=20Q=\dfrac{W}{V}=\dfrac{10^9}{5\times10^7}=20 C.

Step 3 (b). The current is charge divided by time, I=Qt=200.2=100I=\dfrac{Q}{t}=\dfrac{20}{0.2}=100 A.

Step 4 (c). The power delivered is energy divided by time, P=Wt=1090.2=5×109P=\dfrac{W}{t}=\dfrac{10^9}{0.2}=5\times10^9 W =5=5 GW.

Step 5. As a check, P=IV=100×(5×107)=5×109P=IV=100\times(5\times10^7)=5\times10^9 W, confirming the same value by the alternative power formula.

✓Final answer

  1. Charge transferred Q=20Q=20 C.
  2. Current I=100I=100 A.
  3. Power delivered P=5×109P=5\times10^9 W =5=5 GW.

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