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Q.How much time will 102010^{20} electrons take to flow through a point in a conductor so that the current is 200 mA ? [e=1.6×10−19e = 1.6\times10^{-19} C]

Tamil Nadu DgeTamil Nadu HSC (DGE) Board 2017Subjective· 3mImportance★★★★★
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The 102010^{20} electrons take 80 s80\ s to flow past the point for a current of 200 mA200\ mA.

Given: number of electrons n=1020n = 10^{20}; charge of an electron e=1.6×10−19 Ce = 1.6\times10^{-19}\ C; current I=200 mA=0.2 AI = 200\ mA = 0.2\ A.

Step 1 — total charge transferred. The total charge carried by nn electrons is

Q=n e=1020×1.6×10−19 C=1.6×1020−19 C=1.6×10 C=16 CQ = n\,e = 10^{20}\times1.6\times10^{-19}\ C = 1.6\times10^{20-19}\ C = 1.6\times10\ C = 16\ C

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