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Question 109 of 132

Q.(a) Discuss with theory the method of inducing emf in a coil by changing its orientation with respect to the direction of the magnetic field. OR

(b) Explain the working of a half wave diode rectifier.
Tamil Nadu DgeTamil Nadu HSC (DGE) Board 2019Subjective· 5mImportance★★★★★
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(a) Rotating a coil in a uniform magnetic field changes the flux linkage sinusoidally, inducing a sinusoidal alternating emf e=e0sin⁡ωte=e_0\sin\omega t — this is the working principle of an AC generator. (b) A half-wave rectifier uses one diode's one-way conduction to pass only alternate half-cycles of an AC input, producing a pulsating unidirectional output. Both alternatives are answered in full below.

(a) Induced emf by changing the orientation of a coil (AC generator)

Consider a rectangular coil of NN turns and area AA, mounted so that it can rotate about an axis perpendicular to a uniform magnetic field B⃗\vec B, with constant angular velocity ω\omega. Let θ\theta be the angle between the normal to the coil and B⃗\vec B at time tt; if the coil starts in the plane of BB (normal aligned with BB) at t=0t=0, then θ=ωt\theta = \omega t.

The magnetic flux linked with the coil at time tt is

Φ(t)=NBAcos⁡θ=NBAcos⁡ωt\Phi(t) = NBA\cos\theta = NBA\cos\omega t

By Faraday's law of electromagnetic induction, the induced emf is

e=−dΦdt=−NBAddt(cos⁡ωt)=NBAωsin⁡ωte = -\dfrac{d\Phi}{dt} = -NBA\dfrac{d}{dt}(\cos\omega t) = NBA\omega\sin\omega t

Writing e0=NBAωe_0 = NBA\omega (the peak/maximum emf), this is

e=e0sin⁡ωte = e_0\sin\omega t

So as the coil's orientation with respect to B⃗\vec B changes continuously due to rotation, the flux through it varies sinusoidally, and by Faraday's law this induces a sinusoidally alternating emf — reversing direction every half rotation. This is exactly the working principle of an AC generator (alternator): mechanical rotation of a coil (armature) in a magnetic field (produced by field magnets) is converted to alternating emf, collected via slip rings and brushes and delivered to an external circuit.

(b) Half-wave rectifier

A p-n junction diode conducts current easily when forward biased (p-side at higher potential) and blocks current (except a negligible reverse saturation current) when reverse biased. This one-way conduction property is used to convert AC to a unidirectional (pulsating) output.

Circuit: The AC supply is fed to the primary of a step-down transformer; the secondary is connected in series with a diode DD and a load resistor RLR_L, forming a closed loop.

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