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Q.A 300 mm long tube containing 60 cc of sugar solution produces a rotation of 9° when placed in a polarimeter. If the specific rotation is 60°, calculate the quantity of sugar contained in the solution.

Tamil Nadu DgeTamil Nadu HSC (DGE) Board 2017Subjective· 3mImportance★★★★★
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The 60 cc sugar solution in the polarimeter tube contains 3 g of sugar.

The specific rotation of an optically active substance (like sugar in solution) is defined as

[α]=θl c[\alpha] = \frac{\theta}{l\,c}

where θ\theta is the angle of rotation of the plane of polarisation (in degrees), ll is the length of the polarimeter tube expressed in decimetres (dm), and cc is the concentration of the solution in grams per cc (g/mL).

Given: length l=300 mm=30 cm=3 dml = 300\ mm = 30\ cm = 3\ dm; angle of rotation θ=9°\theta = 9°; specific rotation [α]=60°[\alpha] = 60°; volume of solution V=60 ccV = 60\ cc.

Step 1 — find the concentration cc:

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