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Question 169 of 199

Q.Derive the relation between ff and R for a spherical mirror.

Tamil Nadu DgeTamil Nadu HSC (DGE) Board 2022Subjective· 3mImportance★★★★★
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Using the small-angle (paraxial) geometry of a ray reflecting near the pole of a spherical mirror, the relation 2/R=1/u+1/v2/R=1/u+1/v follows, and setting the object at infinity (v=fv=f) gives f=R/2f=R/2.

Working

Consider a concave mirror with pole PP, centre of curvature CC (radius R=PCR=PC), forming an image II of an object OO on the principal axis, using a paraxial ray OMOM striking the mirror at a point MM close to the pole and reflecting to II (normal at MM is along MCMC).

Let α,β,γ\alpha,\beta,\gamma be the (small) angles that OMOM, CMCM, IMIM respectively make with the principal axis, and let θ\theta be the common angle of incidence/reflection at MM (law of reflection).

Using the exterior-angle property of a triangle:

  • In △OMC\triangle OMC: β=α+θ ⇒ θ=β−α\beta=\alpha+\theta\ \Rightarrow\ \theta=\beta-\alpha
  • In △CMI\triangle CMI: γ=β+θ ⇒ θ=γ−β\gamma=\beta+\theta\ \Rightarrow\ \theta=\gamma-\beta

Equating the two expressions for θ\theta:

β−α=γ−β ⇒ 2β=α+γ\beta-\alpha=\gamma-\beta\ \Rightarrow\ 2\beta=\alpha+\gamma

Since MM is close to the pole, for a ray at height hh above the axis, the small angles are (paraxial approximation, tan⁡θ≈θ\tan\theta\approx\theta): …

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