Skip to content
Question 159 of 199

Q.In Newton's rings experiment, obtain an expression for the radius of the nthn^{th} dark ring.

Tamil Nadu DgeTamil Nadu HSC (DGE) Board 2018Subjective· 5mImportance★★★★★
80% · 159/199 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Newton's rings arise from interference in the thin air film between a plano-convex lens and a glass plate; combining the geometric film-thickness relation with the dark-fringe (destructive interference) condition gives rn=nλRr_n=\sqrt{n\lambda R}.

  1. A plano-convex lens of large radius of curvature RR rests with its curved surface on a plane glass plate, enclosing a thin wedge-shaped air film of varying thickness between them.
  2. At a point where the film thickness is tt and the distance from the point of contact is rr, the geometry of the lens surface gives, for small tt (using r2=2Rt−t2≈2Rtr^2 = 2Rt - t^2 \approx 2Rt): t=r22Rt = \frac{r^2}{2R}
  3. For light of wavelength λ\lambda incident normally, the ray reflected at the lower (glass) surface undergoes an additional phase change of π\pi (path difference λ/2\lambda/2) because this reflection occurs at a denser medium; so the effective path difference between the two reflected rays is Δ=2t+λ/2\Delta = 2t + \lambda/2. …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.