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Q.Light of wavelength of 5000 Å produces diffraction pattern of the single slit of width 5 μ\mum. What is the maximum order of diffraction possible ?

Tamil Nadu DgeTamil Nadu HSC (DGE) Board 2026Subjective· 2mImportance★★★★★
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Setting sin⁡θ=1\sin\theta=1 in the single-slit minimum condition gives a/λ=10a/\lambda=10; since this exact-integer value corresponds to the unobservable grazing angle, the maximum attainable diffraction order is n=9n=9.

Working

Single-slit diffraction minima occur at

asin⁡θn=nλ ⇒ sin⁡θn=nλaa\sin\theta_n = n\lambda \ \Rightarrow\ \sin\theta_n = \dfrac{n\lambda}{a}

Since sin⁡θn\sin\theta_n cannot exceed 1, the maximum possible order satisfies

n≤aλn \le \dfrac{a}{\lambda}

Given: a=5 μm=5×10−6a=5\ \mu\text{m}=5\times10^{-6} m, λ=5000 A˚=5×10−7\lambda=5000\ \text{\AA}=5\times10^{-7} m.

aλ=5×10−65×10−7=10\dfrac{a}{\lambda} = \dfrac{5\times10^{-6}}{5\times10^{-7}} = 10

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