Skip to content
Exercises · 7.23

Q.Why are halogens strong oxidising agents?

Telangana TsbieTextbookSubjectiveImportance★★★★★est
47% · 45/96 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Step 1: The oxidation process.

A halogen X2X_2 acts as an oxidising agent by accepting electrons and being reduced to halide ions:

X2+2e−→2X−X_2 + 2e^- \rightarrow 2X^-

This overall process can be broken into three energetic steps: (i) breaking the X–X bond,

(ii) electron gain by each X atom,

(iii) hydration of the resulting X−X^- ion.

Step 2: Low bond dissociation enthalpy.

The X–X bond in halogens is relatively weak (especially for Cl2,Br2,I2Cl_2, Br_2, I_2), so relatively little energy is needed to generate free halogen atoms as the first step towards accepting electrons.

Step 3: High (negative) electron gain enthalpy.

Halogens have a strong tendency to gain one electron and complete a stable octet, releasing a large amount of energy (highly negative electron gain enthalpy), which strongly favours formation of X−X^-.

Step 4: High hydration enthalpy.

The small, singly-charged X−X^- ions are strongly hydrated (or solvated) in aqueous/other solution, releasing a large hydration enthalpy that further stabilises the X−X^- ion once formed.

Step 5: Net effect. …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.