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Exercises · 4.2

Q.Write Lewis dot symbols for atoms of the following elements: Mg, Na, B, O, N, Br.

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Lewis dot symbols place valence electrons as dots around the element symbol, showing only the outermost shell electrons that participate in bonding. For the six elements: Mg has 2 dots, Na has 1, B has 3, O has 6, N has 5, and Br has 7.

The Lewis dot structure (or electron-dot symbol) is a notation invented by Gilbert N. Lewis to represent the valence electrons of an atom—those electrons in the outermost shell that determine chemical behavior. The element symbol represents the nucleus plus all inner electrons (the "core"), while dots around it show only the valence electrons.

Why does this matter? Chemical bonding involves valence electrons. Atoms form bonds by sharing, gaining, or losing these outer electrons to achieve stable configurations. The Lewis symbol gives us an instant visual of how many electrons an atom can offer for bonding.

The convention is straightforward: write the element symbol, then place dots around it (top, right, bottom, left) to represent valence electrons. When there are more than four electrons, start pairing them up.

Let me work through each element by identifying its valence electron count from its position in the periodic table.


1. Magnesium (Mg)

Magnesium is in Group 2, so it has 2 valence electrons. Its electronic configuration is 1s2 2s2 2p6 3s21s^2 \, 2s^2 \, 2p^6 \, 3s^2—the two electrons in the 3s3s subshell are the valence electrons.

Mg ⋅⋅\mathrm{Mg}\, \cdot \cdot

or more symmetrically:

⋅ Mg ⋅\cdot \, \mathrm{Mg} \, \cdot


2. Sodium (Na)

Sodium is in Group 1, giving it 1 valence electron. Configuration: 1s2 2s2 2p6 3s11s^2 \, 2s^2 \, 2p^6 \, 3s^1.

Na ⋅\mathrm{Na} \, \cdot


3. Boron (B)

Boron is in Group 13, so it has 3 valence electrons. Configuration: 1s2 2s2 2p11s^2 \, 2s^2 \, 2p^1.

⋅ B ⋅\cdot \, \mathrm{B} \, \cdot

⋅ B ⋅\phantom{\cdot \, \mathrm{B}} \, \cdot

or arranged around the symbol:

⋅⋅ B ⋅\begin{array}{c} \cdot \\ \cdot \, \mathrm{B} \, \cdot \end{array}


4. Oxygen (O)

Oxygen is in Group 16, so it has 6 valence electrons. Configuration: 1s2 2s2 2p41s^2 \, 2s^2 \, 2p^4.

Following the convention of placing one electron on each side first, then pairing:

⋅⋅O⋅⋅\begin{array}{c} \cdot \cdot \\ \mathrm{O} \\ \cdot \cdot \end{array}

or written horizontally: ⋅⋅ O ⋅⋅\cdot \cdot \, \mathrm{O} \, \cdot \cdot with two pairs and two singles.


5. Nitrogen (N)

Nitrogen is in Group 15, so it has 5 valence electrons. Configuration: 1s2 2s2 2p31s^2 \, 2s^2 \, 2p^3.

⋅⋅N ⋅⋅\begin{array}{c} \cdot \cdot \\ \mathrm{N} \, \cdot \\ \cdot \end{array}

One pair and three unpaired electrons.


6. Bromine (Br)

Bromine is in Group 17 (the halogens), so it has 7 valence electrons. Configuration ends in 4s2 4p54s^2 \, 4p^5.

⋅⋅⋅ Br ⋅⋅\begin{array}{c} \cdot \cdot \\ \cdot \, \mathrm{Br} \, \cdot \cdot \\ \end{array}

Three pairs and one unpaired electron.


Tip

The number of valence electrons equals the group number for main-group elements: Group 1 → 1 electron, Group 2 → 2 electrons, Groups 13–18 → subtract 10 (so Group 15 → 5 electrons, Group 17 → 7 electrons).

Watch out

Do not confuse the total number of electrons with valence electrons. Only the outermost shell counts. For example, oxygen has 8 total electrons but only 6 valence electrons.


✓Final answer

The Lewis dot symbols are: ⋅ Mg ⋅\cdot \, \mathrm{Mg} \, \cdot (2 dots), Na ⋅\mathrm{Na} \, \cdot (1 dot), ⋅ B⋅⋅\cdot \, \mathrm{B} \begin{array}{c} \cdot \\ \cdot \end{array} (3 dots), ⋅⋅O⋅⋅\begin{array}{c} \cdot \cdot \\ \mathrm{O} \\ \cdot \cdot \end{array} (6 dots), ⋅⋅N ⋅⋅\begin{array}{c} \cdot \cdot \\ \mathrm{N} \, \cdot \\ \cdot \end{array} (5 dots), and ⋅⋅⋅ Br ⋅⋅\begin{array}{c} \cdot \cdot \\ \cdot \, \mathrm{Br} \, \cdot \cdot \end{array} (7 dots).

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