Q.What is the total number of sigma and pi bonds in the following molecules?
You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.
Start your 14-day free trial to unlock the full solution →The key is to draw the Lewis structure and count every single bond as one sigma bond, every double bond as one sigma + one pi, and every triple bond as one sigma + two pi. For (a) (ethyne): 3 sigma, 2 pi bonds. For (b) (ethene): 5 sigma, 1 pi bond.
Why bond order matters
A sigma bond is the first, strongest bond formed between two atoms — it lies directly along the internuclear axis. Any additional bond between the same pair of atoms must be a pi bond, formed by sideways overlap of p-orbitals. So:
- Single bond = 1 sigma, 0 pi
- Double bond = 1 sigma, 1 pi
- Triple bond = 1 sigma, 2 pi
This rule is absolute. Once you know the connectivity and bond types in a molecule, counting becomes mechanical.
(a) — Ethyne (acetylene)
-
Draw the structure. Each carbon needs four bonds. Hydrogen can only form one bond. The only way to satisfy both carbons is a triple bond between them, with each carbon also bonded to one hydrogen:
-
Count sigma bonds. Every single bond is sigma. The triple bond contains one sigma bond. So:
- bonds: 2 sigma
- bond: 1 sigma Total sigma =
-
Count pi bonds. The triple bond contributes two pi bonds (the remaining two bonds in the triple bond). No other multiple bonds exist.
Total pi =
In a triple bond, think: "one sigma, two pi" — the pi bonds are the extra two that make it a triple.
--- …
Unlock everything free for 14 days
- Full step-by-step solutions
- Concept-first explanations
- Methods, shortcuts & mistakes
- PYQ mapping + timed mock tests
Full access for 14 days. No credit card required.