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Exercises · 4.22

Q.Explain why BeH2BeH_2 molecule has a zero dipole moment although the Be–H bonds are polar.

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The key idea is that molecular dipole moment depends on both bond polarity and molecular geometry. Although Be–H bonds are polar (Be is less electronegative than H), BeH2BeH_2 is linear with symmetric bond dipoles that cancel exactly, giving a net zero dipole moment.

Why This Approach Works

The dipole moment of a molecule is a vector sum of all individual bond dipole moments. A common mistake is to assume that polar bonds always produce a polar molecule — but that’s only true if the bond dipoles do not cancel. The geometry of the molecule determines whether the vectors add or cancel. For BeH2BeH_2, the linear shape means the two Be–H bond dipoles point in exactly opposite directions, so their vector sum is zero.

Watch out

Never judge molecular polarity by bond polarity alone. Even molecules with highly polar bonds (like CO2CO_2 or BeH2BeH_2) can be nonpolar if their shape is symmetric.

Step-by-Step Reasoning

  1. Understand bond polarity in Be–H

    Electronegativity values: Be ≈ 1.57, H ≈ 2.20. The difference is about 0.63, which is significant enough to make the Be–H bond polar. The electron density is pulled toward hydrogen, so each bond has a dipole moment pointing from Be (positive end) toward H (negative end).

  2. Determine the molecular geometry of BeH2BeH_2

    Beryllium has only two valence electrons and forms two sigma bonds with hydrogen. There are no lone pairs on Be. According to VSEPR theory, the electron pairs repel to maximize separation, giving a linear geometry with a bond angle of 180∘180^\circ.

  3. Represent bond dipoles as vectors

    Each Be–H bond dipole is a vector of equal magnitude (since both bonds are identical) pointing from Be to H. In a linear molecule, these two vectors lie along the same line but point in opposite directions.

  4. Add the vectors

    Vector addition: …

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