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Example · Example 35

Q.Outline the mechanism of the Friedel-Crafts acylation of benzene with acetyl chloride and anhydrous AlCl3\text{AlCl}_3, and explain why this reaction avoids the problems seen in alkylation.

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Anhydrous AlCl3\text{AlCl}_3 coordinates to the chlorine of acetyl chloride, CH3COCl\text{CH}_3\text{COCl}, and helps it ionise to generate an acylium ion, CH3–C≡O+\text{CH}_3\text{--C}{\equiv}\text{O}^+, which is significantly stabilised by resonance delocalisation of the positive charge between the carbon and the oxygen (CH3–C≡O+↔CH3–C+=O\text{CH}_3\text{--C}{\equiv}\text{O}^+ \leftrightarrow \text{CH}_3\text{--}\overset{+}{\text{C}}{=}\text{O}). This acylium ion then attacks the ring by the usual EAS mechanism -- forming the resonance-stabilised arenium ion, then losing H+\text{H}^+ to rearomatise -- to give the aryl ketone, acetophenone, C6H5COCH3\text{C}_6\text{H}_5\text{COCH}_3. This avoids alkylation's two problems for two distinct reasons. Because the acylium ion is ALREADY resonance-stabilised, it has no comparably favourable rearrangement pathway available (unlike a simple alkyl carbocation, which can gain stability by rearranging), so the acyl group transfers to the ring intact, without skeletal rearrangement. And because the resulting ketone's carbonyl group is electron-WITHDRAWING (inductively pulling electron density out of the ring, unlike an alkyl group's electron-donating effect), the acetophenone product is LESS reactive toward further electrophilic substitution than benzene itself -- so the reactio …

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