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Exercise · Q18

Q.State the structural condition needed for an alkene to show geometrical isomerism, and determine whether

(a) pent-1-ene and
(b) pent-2-ene can show it.
West Bengal WbchseTextbookSubjectiveImportance★★★★★
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An alkene R1R2C=CR3R4\text{R}_1\text{R}_2\text{C=CR}_3\text{R}_4 shows geometrical isomerism only if R1≠R2\text{R}_1 \neq \text{R}_2 on one double-bond carbon AND R3≠R4\text{R}_3 \neq \text{R}_4 on the other -- neither carbon may carry two identical groups. (a) Pent-1-ene, CH2=CHCH2CH2CH3\text{CH}_2{=}\text{CHCH}_2\text{CH}_2\text{CH}_3, has its double bond at the very end of the chain, so the terminal carbon carries two hydrogens -- identical groups -- and the condition fails; pent-1-ene shows no cis-trans isomerism. …

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