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Miscellaneous · Q27

Q.Prove that the line through the points (2,−3)(2, -3) and (−4,5)(-4, 5) is parallel to the line through the points (5,1)(5, 1) and (−1,9)(-1, 9), and find the distance between these two parallel lines.

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Slope of the line through (2,−3)(2,-3) and (−4,5)(-4,5): 5−(−3)−4−2=8−6=−43\dfrac{5-(-3)}{-4-2}=\dfrac{8}{-6}=-\dfrac43. Slope of the line through (5,1)(5,1) and (−1,9)(-1,9): 9−1−1−5=8−6=−43\dfrac{9-1}{-1-5}=\dfrac{8}{-6}=-\dfrac43. Since both slopes equal −43-\dfrac43, the two lines are parallel. Their equations (point-slope through each pair, cleared of fractions): first line through (2,−3)(2,-3): y+3=−43(x−2)  ⟹  3y+9=−4x+8  ⟹  4x+3y+1=0y+3=-\dfrac43(x-2) \implies 3y+9=-4x+8 \implies 4x+3y+1=0 (check with (−4,5)(-4,5): −16+15+1=0-16+15+1=0 ✓). Second line through (5,1)(5,1): y−1=−43(x−5)  ⟹  3y−3=−4x+20  ⟹  4x+3y−23=0y-1=-\dfrac43(x-5) \implies 3y-3=-4x+20 \implies 4x+3y-23=0 (check w …

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