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Practice Questions · Q9

Q.Find the distance between the points (−2,−3)(-2, -3) and (2,0)(2, 0).

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✓ Free question

Using the distance formula with (x1,y1)=(−2,−3)(x_1,y_1)=(-2,-3) and (x2,y2)=(2,0)(x_2,y_2)=(2,0):

d=(2−(−2))2+(0−(−3))2=42+32=16+9=25=5d=\sqrt{(2-(-2))^2+(0-(-3))^2}=\sqrt{4^2+3^2}=\sqrt{16+9}=\sqrt{25}=5

✓Final answer

Distance =5=5 units

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