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Example · Example 10

Q.Glycine and alanine combine to form a dipeptide. Show how the peptide bond is formed between them, and state what small molecule is released in the process.

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Peptide bond formation is a condensation reaction between the carboxyl group (−COOH-\text{COOH}) of one amino acid and the amino group (−NH2-\text{NH}_2) of a second amino acid. Taking glycine's carboxyl group and alanine's amino group as the reacting pair: the −OH-\text{OH} from glycine's −COOH-\text{COOH} combines with one hydrogen from alanine's −NH2-\text{NH}_2 to split off as one molecule of H2O\text{H}_2\text{O}, while the remaining carbon (from glycine's former carboxyl) and nitrogen (from alanine's former amino group) become directly bonded to each other, forming the amide linkage −CO−NH−-\text{CO}{-}\text{NH}{-} -- this specific amide bond, when it joins two amino acid units, is called the peptide bond. …

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