Question 46 of 48
Q.Which of the following compounds will give racemic mixture on SN1 reaction with aqueous KOH? (I) CH3-CH(C2H5)-Br, (II) CH3-C(CH3)(C2H5)-Br, (III) CH3-CH(CH3)-CH2Br, (IV) CH3-CH2-CH2-CH2-Br
(a) I
(b) II
(c) III
(d) IV
West Bengal WbchseWest Bengal HS (WBCHSE) Board 2026MCQ· 1mImportance★★★★★
96% · 46/48 Questions
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Start your 14-day free trial to unlock the full solution →A racemic product in SN1 requires the reacting carbon to be a chiral centre. Only (I) 2-bromobutane has four different groups on the C-Br carbon, so its SN1 gives a racemic mixture. Correct option (a).
SN1 proceeds via a planar (sp2) carbocation, which is attacked by the nucleophile from both faces. This gives a racemic (50:50) mixture only if the reacting carbon was a stereocentre (four different groups) so that the two faces lead to enantiomers.
Checking each:
- (I) CH3-CH(C2H5)-Br = 2-bromobutane: the C-Br carbon bears CH3, C2H5, H, Br - four different groups (chiral). SN1 -> racemic mixture. Correct. …
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