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Question 48 of 52

Q.If A=[1221]A = \begin{bmatrix} 1 & 2 \\ 2 & 1 \end{bmatrix} and f(x)=x2−2x−5f(x) = x^2 - 2x - 5, then f(A)f(A) is equal to

(a) [−200−2]\begin{bmatrix} -2 & 0 \\ 0 & -2 \end{bmatrix}
(b) [−300−3]\begin{bmatrix} -3 & 0 \\ 0 & -3 \end{bmatrix}
(c) [2003]\begin{bmatrix} 2 & 0 \\ 0 & 3 \end{bmatrix}
(d) [−300−2]\begin{bmatrix} -3 & 0 \\ 0 & -2 \end{bmatrix}
West Bengal WbchseWest Bengal HS (WBCHSE) Board 2026MCQ· 1mImportance★★★★★
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Evaluate the matrix polynomial f(A)=A2−2A−5If(A)=A^2-2A-5I; the scalar 55 becomes 5I5I.

Evaluating a polynomial at a matrix argument is a standard NCERT/CBSE Class 12 matrices exercise.

First A2A^2:

A2=[1221][1221]=[5445].A^2 = \begin{bmatrix}1&2\\2&1\end{bmatrix}\begin{bmatrix}1&2\\2&1\end{bmatrix} = \begin{bmatrix}5&4\\4&5\end{bmatrix}.

Then 2A=[2442]2A = \begin{bmatrix}2&4\\4&2\end{bmatrix} and 5I=[5005]5I = \begin{bmatrix}5&0\\0&5\end{bmatrix}.

So …

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