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Question 47 of 52

Q.If A=[aij]A = [a_{ij}] is a 2×22 \times 2 matrix, where aij=12(i+2j)2a_{ij} = \dfrac{1}{2}(i + 2j)^2, then AA is

(a) [92252818]\begin{bmatrix} \dfrac{9}{2} & \dfrac{25}{2} \\ 8 & 18 \end{bmatrix}
(b) [9252818]\begin{bmatrix} 9 & \dfrac{25}{2} \\ 8 & 18 \end{bmatrix}
(c) [9225289]\begin{bmatrix} \dfrac{9}{2} & \dfrac{25}{2} \\ 8 & 9 \end{bmatrix}
(d) [92152418]\begin{bmatrix} \dfrac{9}{2} & \dfrac{15}{2} \\ 4 & 18 \end{bmatrix}
West Bengal WbchseWest Bengal HS (WBCHSE) Board 2026MCQ· 1mImportance★★★★★
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Substitute each (i,j)(i,j) into aij=12(i+2j)2a_{ij}=\tfrac12(i+2j)^2 to build the matrix.

Building a matrix from a formula for its entries is a core CBSE/NCERT Class 12 matrices skill.

Compute each entry of the 2×22\times2 matrix:

a11=12(1+2)2=12⋅9=92,a_{11} = \tfrac12(1+2)^2 = \tfrac12\cdot 9 = \tfrac{9}{2},

a12=12(1+4)2=12⋅25=252,a_{12} = \tfrac12(1+4)^2 = \tfrac12\cdot 25 = \tfrac{25}{2},

a21=12(2+2)2=12⋅16=8,a_{21} = \tfrac12(2+2)^2 = \tfrac12\cdot 16 = 8, …

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