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Question 42 of 52

Q.If 2X + 3Y = (2 3; 4 0) and 3X + 2Y = (2 -2; -1 5), find X and Y. OR If A = (3 1; -1 2), show that A² - 5A + 7I = 0.

West Bengal WbchseWest Bengal HS (WBCHSE) Board 2023Subjective· 4mImportance★★★★★
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Two matrix equations in X,YX,Y are solved exactly like two scalar simultaneous equations — eliminate one unknown by scaling and subtracting.

Step 1. Given 2X+3Y=[2340]2X+3Y=\begin{bmatrix}2&3\\4&0\end{bmatrix} (i) and 3X+2Y=[2−2−15]3X+2Y=\begin{bmatrix}2&-2\\-1&5\end{bmatrix} (ii).

Step 2. Eliminate XX: multiply (i) by 33 and (ii) by 22:

6X+9Y=[69120],6X+4Y=[4−4−210].6X+9Y=\begin{bmatrix}6&9\\12&0\end{bmatrix},\qquad 6X+4Y=\begin{bmatrix}4&-4\\-2&10\end{bmatrix}.

Subtract: 5Y=[21314−10]5Y=\begin{bmatrix}2&13\\14&-10\end{bmatrix}, so Y=[2/513/514/5−2]Y=\begin{bmatrix}2/5 & 13/5\\ 14/5 & -2\end{bmatrix}.

Step 3. Substitute back into (i): 2X=[2340]−3Y=[2340]−[6/539/542/5−6]=[4/5−24/5−22/56]2X = \begin{bmatrix}2&3\\4&0\end{bmatrix}-3Y=\begin{bmatrix}2&3\\4&0\end{bmatrix}-\begin{bmatrix}6/5&39/5\\42/5&-6\end{bmatrix}=\begin{bmatrix}4/5&-24/5\\-22/5&6\end{bmatrix}. …

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