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Question 33 of 52

Q.A = [[8, 0], [4, -2]] and B = [[2, -2], [-5, 1]], find another matrix X where 2A + 3X = 5B.

West Bengal WbchseWest Bengal HS (WBCHSE) Board 2019Subjective· 2mImportance★★★★★
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Solve 2A+3X=5B2A+3X=5B for XX by matrix subtraction and scalar division.

Given A=[804−2]A=\begin{bmatrix}8&0\\4&-2\end{bmatrix}, B=[2−2−51]B=\begin{bmatrix}2&-2\\-5&1\end{bmatrix}, and 2A+3X=5B2A+3X=5B.

3X=5B−2A3X = 5B - 2A

5B=[10−10−255],2A=[1608−4]5B=\begin{bmatrix}10&-10\\-25&5\end{bmatrix},\qquad 2A=\begin{bmatrix}16&0\\8&-4\end{bmatrix}

5B−2A=[10−16−10−0−25−85−(−4)]=[−6−10−339]5B-2A=\begin{bmatrix}10-16 & -10-0\\-25-8 & 5-(-4)\end{bmatrix}=\begin{bmatrix}-6&-10\\-33&9\end{bmatrix}

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