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Question 37 of 55

Q.(a) Define relaxation time of the free electron drifting in a conductor.

(b) Derive an expression for the resistivity of a good conductor, in terms of the relaxation time of the free electrons.
(c) Estimate the average drift speed of conduction electrons in a copper wire of cross-sectional area 2.5×10^-7 m² carrying a current of 1.8 A. Assume the density of conduction electrons to be 9×10^28 m^-3. OR
(a) State the principle of a potentiometer.
(b) A potentiometer wire of length 1.0 m has a resistance of 15 Ω. It is connected to a 5 V battery in series with a resistance of 5 Ω. Determine the emf of the primary cell which gives a balance point at 0.6 m.
(c) Describe briefly with the help of a circuit diagram, how a potentiometer is used to determine the internal resistance of a cell.
West Bengal WbchseWest Bengal HS (WBCHSE) Board 2022Subjective· 5mImportance★★★★★
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Resistivity follows from the drift-velocity (Drude) model as ρ=m/ne2τ\rho=m/ne^2\tau; here the drift speed works out to 0.50.5 mm/s.

(a) Relaxation time (τ\tau): It is the average time interval between two successive collisions of a free (conduction) electron with the ions/atoms of the conductor's lattice, as it drifts under an applied electric field.

(b) Derivation of resistivity: In an electric field EE, a free electron of charge −e-e and mass mm experiences force eEeE, giving acceleration a=eE/ma=eE/m. Between collisions (average duration τ\tau), it gains an average drift velocity

vd=aτ=eEτmv_d = a\tau = \frac{eE\tau}{m}

If nn is the free-electron density, the current density is J=nevd=ne2τmEJ=nev_d = \dfrac{ne^2\tau}{m}E. Comparing with J=σE=E/ρJ=\sigma E = E/\rho: …

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