Question 54 of 55
Q.A wire of length l and resistance R is stretched till its length becomes x times its original length. Its new resistance will be
(a) x²R
(b) xR
(c) R / x
(d) R
West Bengal WbchseWest Bengal HS (WBCHSE) Board 2026MCQ· 1mImportance★★★★★
98% · 54/55 Questions
You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.
Start your 14-day free trial to unlock the full solution →Stretching keeps volume constant: length ×x means area ÷x. Since R = ρl/A, the new resistance scales as x², giving x²R. Option (a).
Step 1 — volume conservation: A·l = A'·l'. With l' = x·l, the new area A' = A/x.
Step 2 — new resistance:
R' = ρ l'/A' = ρ(x l)/(A/x) = x²·(ρl/A) = x²R.
…
Unlock everything free for 14 days
- Full step-by-step solutions
- Concept-first explanations
- Methods, shortcuts & mistakes
- PYQ mapping + timed mock tests
Full access for 14 days. No credit card required.