Q.Why does the reactivity of nitrogen differ from phosphorus?
Step 1: Bonding in elemental nitrogen.
Nitrogen's small atomic size allows effective sideways (–) overlap between two N atoms, giving the very strong triple bond in (bond enthalpy ). This exceptionally strong bond makes kinetically and thermodynamically very stable/unreactive at ordinary temperatures.
Step 2: Bonding in elemental phosphorus.
Phosphorus is a larger atom, so effective – overlap between two P atoms is not possible (the atomic orbitals are too diffuse/far apart for good sideways overlap). Phosphorus therefore cannot form a stable triple bond, and instead catenates through single P–P bonds, existing as tetrahedral molecules.
Step 3: Comparing bond strengths.
A single P–P bond is considerably weaker than the N≡N triple bond, so is far more reactive than — white phosphorus even ignites spontaneously in air, while requires very forcing conditions (e.g. lightning, or the Haber process catalyst/high pressure/temperature) to react.
Step 4: Role of d-orbitals.
Additionally, phosphorus has accessible 3d orbitals allowing it to expand its octet and form a wider variety of compounds/oxidation states more readily than nitrogen (2p, no d-orbitals), which also contributes to phosphorus's greater chemical versatility/reactivity.
Nitrogen's small size gives strong – overlap and a very strong N≡N bond, making inert; phosphorus's larger size prevents such multiple bonding, so it exists as held by weaker P–P single bonds, making phosphorus far more reactive.
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