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Exercises · 7.2

Q.Why does the reactivity of nitrogen differ from phosphorus?

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Step 1: Bonding in elemental nitrogen.

Nitrogen's small atomic size allows effective sideways (pπp\pi–pπp\pi) overlap between two N atoms, giving the very strong triple bond in N≡NN \equiv N (bond enthalpy ≈941 kJ mol−1\approx 941\ kJ\,mol^{-1}). This exceptionally strong bond makes N2N_2 kinetically and thermodynamically very stable/unreactive at ordinary temperatures.

Step 2: Bonding in elemental phosphorus.

Phosphorus is a larger atom, so effective pπp\pi–pπp\pi overlap between two P atoms is not possible (the atomic orbitals are too diffuse/far apart for good sideways overlap). Phosphorus therefore cannot form a stable P≡PP \equiv P triple bond, and instead catenates through single P–P σ\sigma bonds, existing as tetrahedral P4P_4 molecules.

Step 3: Comparing bond strengths.

A single P–P bond is considerably weaker than the N≡N triple bond, so P4P_4 is far more reactive than N2N_2 — white phosphorus even ignites spontaneously in air, while N2N_2 requires very forcing conditions (e.g. lightning, or the Haber process catalyst/high pressure/temperature) to react.

Step 4: Role of d-orbitals.

Additionally, phosphorus has accessible 3d orbitals allowing it to expand its octet and form a wider variety of compounds/oxidation states more readily than nitrogen (2p, no d-orbitals), which also contributes to phosphorus's greater chemical versatility/reactivity.

✓Final answer

Nitrogen's small size gives strong pπp\pi–pπp\pi overlap and a very strong N≡N bond, making N2N_2 inert; phosphorus's larger size prevents such multiple bonding, so it exists as P4P_4 held by weaker P–P single bonds, making phosphorus far more reactive.

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