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Exercises · 7.8

Q.Give the resonating structures of NO2 and N2O5.

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Step 1: NO2NO_2 resonance.

NO2NO_2 has one unpaired electron on nitrogen (17 valence electrons total, odd number) and is bent/angular. It is represented as a resonance hybrid of two equivalent structures in which the N=O double bond and the N–O single bond (and the odd electron) are interchanged between the left and right oxygen atoms:

O=N∙−O−  ↔  −O−N∙=OO=N^{\bullet}-O^- \;\leftrightarrow\; ^-O-N^{\bullet}=O

(the odd electron is formally shown on N, delocalised over the N–O framework in the true hybrid), giving both N–O bonds equal, intermediate bond order/length in the real molecule.

Step 2: N2O5N_2O_5 structure.

N2O5N_2O_5 (dinitrogen pentoxide) consists of two planar NO3NO_3 (nitrate-like) units connected through a bridging oxygen atom (–O–), i.e. O2NO_2N–O–NO2NO_2, with each terminal NO2NO_2 group itself carrying a positive nitrogen bonded to two terminal oxygens.

Step 3: N2O5N_2O_5 resonance.

Each terminal –NO2–NO_2 group (like the nitrate ion) is a resonance hybrid, with the N=O double bond character delocalised between its two terminal oxygen atoms:

O=N(−O−)−O−  ↔  −O−N(−O−)=OO=N(-O-)-O^- \;\leftrightarrow\; ^-O-N(-O-)=O …

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