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Question Bank (2 marks) · Q8

Q.Explain how stability is achieved in negative feedback amplifier.

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[!TLDR]

Because Af≈1/βA_f \approx 1/\beta when Aβ≫1A\beta \gg 1, the gain depends only on the passive feedback network, so it stays constant despite changes in the amplifier itself.

The closed-loop gain of a negative-feedback amplifier is

Af=A1+Aβ.A_f = \frac{A}{1 + A\beta}.

When the loop gain is large, Aβ≫1A\beta \gg 1, the '1' is negligible and

Af≈AAβ=1β.A_f \approx \frac{A}{A\beta} = \frac{1}{\beta}.

The gain now depends only on β\beta, which is fixed by stable passive resistors, so it is unaffected by changes in transistor parameters, supply voltage or ageing.

This can be shown quantitatively by differentiating AfA_f with respect to AA:

dAfAf=dAA×11+Aβ.\frac{dA_f}{A_f} = \frac{dA}{A} \times \frac{1}{1 + A\beta}. …

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