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Question Bank (5 marks) · Q6

Q.Explain the effect of negative feedback on stability of the gain.

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[!TLDR]

Negative feedback makes Af≈1/βA_f \approx 1/\beta and reduces any fractional change in gain by (1+Aβ)(1+A\beta), so the overall gain stays almost constant.

The voltage gain of a transistor amplifier varies with device parameters, supply voltage, temperature and ageing, so the open-loop gain AA is not constant. Negative feedback stabilises the overall gain.

Gain depends only on β\beta. The closed-loop gain is

Af=A1+Aβ.A_f = \frac{A}{1 + A\beta}.

When the loop gain is large, Aβ≫1A\beta \gg 1, the '1' is negligible:

Af≈AAβ=1β.A_f \approx \frac{A}{A\beta} = \frac{1}{\beta}.

Now the gain is fixed by β\beta, which is set by stable passive components (resistors, capacitors, inductors), and is essentially independent of the amplifier's own parameters.

Quantitative measure of stability. Differentiate AfA_f with respect to AA:

dAfdA=(1+Aβ)−Aβ(1+Aβ)2=1(1+Aβ)2.\frac{dA_f}{dA} = \frac{(1 + A\beta) - A\beta}{(1 + A\beta)^2} = \frac{1}{(1 + A\beta)^2}.

Multiplying and dividing the right-hand side by AA and using Af=A/(1+Aβ)A_f = A/(1+A\beta):

dAfAf=dAA×11+Aβ.\frac{dA_f}{A_f} = \frac{dA}{A} \times \frac{1}{1 + A\beta}. …

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