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Exercise 4.6 · Q122

Q.Evaluate: [321][2−43]\begin{bmatrix} 3 \\ 2 \\ 1 \end{bmatrix} \begin{bmatrix} 2 & -4 & 3 \end{bmatrix}

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✓ Free question

Let P=[321]P=\begin{bmatrix}3\\2\\1\end{bmatrix}, order 3×13\times1, and Q=[2−43]Q=\begin{bmatrix}2 & -4 & 3\end{bmatrix}, order 1×31\times3.

Since the number of columns of PP (=1) equals the number of rows of QQ (=1), the product PQPQ is defined and has order 3×33\times3 — every entry (PQ)ij=Pi1⋅Q1j(PQ)_{ij}=P_{i1}\cdot Q_{1j}.

Row 1 (multiply QQ by P11=3P_{11}=3): 3(2)=6, 3(−4)=−12, 3(3)=9⇒[6 −12 9]3(2)=6,\ 3(-4)=-12,\ 3(3)=9 \Rightarrow [6\ {-12}\ 9]

Row 2 (multiply QQ by P21=2P_{21}=2): 2(2)=4, 2(−4)=−8, 2(3)=6⇒[4 −8 6]2(2)=4,\ 2(-4)=-8,\ 2(3)=6 \Rightarrow [4\ {-8}\ 6]

Row 3 (multiply QQ by P31=1P_{31}=1): 1(2)=2, 1(−4)=−4, 1(3)=3⇒[2 −4 3]1(2)=2,\ 1(-4)=-4,\ 1(3)=3 \Rightarrow [2\ {-4}\ 3]

∴PQ=[6−1294−862−43]\therefore PQ=\begin{bmatrix}6 & -12 & 9\\4 & -8 & 6\\2 & -4 & 3\end{bmatrix}

✓Final answer

[6−1294−862−43]\begin{bmatrix} 6 & -12 & 9 \\ 4 & -8 & 6 \\ 2 & -4 & 3 \end{bmatrix}

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