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Exercise 4.6 · Q123

Q.Evaluate: [2−13][431]\begin{bmatrix} 2 & -1 & 3 \end{bmatrix} \begin{bmatrix} 4 \\ 3 \\ 1 \end{bmatrix}

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✓ Free question

Let P=[2 −1 3]P=[2\ {-1}\ 3], order 1×31\times3, and Q=[431]Q=\begin{bmatrix}4\\3\\1\end{bmatrix}, order 3×13\times1.

Since the number of columns of PP (=3) equals the number of rows of QQ (=3), the product PQPQ is defined and has order 1×11\times1.

PQ=2(4)+(−1)(3)+3(1)=8−3+3=8PQ = 2(4)+(-1)(3)+3(1) = 8-3+3 = 8

∴PQ=[8]\therefore PQ=[8]

✓Final answer

[8][8]

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