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Exercise 4.6 · Q150

Q.Jay and Ram are two friends in a class. Jay wanted to buy 4 pens and 8 notebooks, Ram wanted to buy 5 pens and 12 notebooks. Both of them went to a shop. The price of a pen and a notebook which they have selected was Rs.6 and Rs.10. Using Matrix multiplication, find the amount required from each one of them.

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Let the requirements matrix (rows = Jay, Ram; columns = pens, notebooks) be R=[48512]R=\begin{bmatrix}4&8\\5&12\end{bmatrix} (Jay wants 4 pens, 8 notebooks; Ram wants 5 pens, 12 notebooks), and the price column matrix be P=[610]P=\begin{bmatrix}6\\10\end{bmatrix} (pen = Rs.6, notebook = Rs.10).

Compute RPRP (2×22\times2 times 2×12\times1 = 2×12\times1, each row giving one person's total cost):

Jay's row: 4(6)+8(10)=24+80=1044(6)+8(10)=24+80=104 …

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