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MISCELLANEOUS EXERCISE - 2 (II) · Q117

Q.Find 2×6+4×9+6×12+⋯2\times6+4\times9+6\times12+\cdots upto nn terms.

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First factors 2,4,6,…2,4,6,\ldots: tr=2rt_r=2r. Second factors 6,9,12,…6,9,12,\ldots: tr=3r+3t_r=3r+3. Term =2r(3r+3)=6r2+6r=2r(3r+3)=6r^2+6r. $S_n=6\cdot\dfrac{n(n+1)(2n+1)}6+6\cdot\dfrac{n(n+1)}2=n(n+1) …

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