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MISCELLANEOUS EXERCISE - 2 (II) · Q128

Q.If for a G.P. first term is (27)2(27)^2 and seventh term is (8)2(8)^2, find S8S_8.

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a=729,t7=ar6=64⇒r6=64729=(23)6⇒r=23a=729, t_7=ar^6=64 \Rightarrow r^6=\dfrac{64}{729}=\left(\dfrac23\right)^6 \Rightarrow r=\dfrac23. S8=729[1−(2/3)8]1−2/3=729×3(1−2566561)=2187−2187×2566561S_8=\dfrac{729\left[1-(2/3)^8\right]}{1-2/3}=729\times3\left(1-\dfrac{256}{6561}\right)=2187-\dfrac{2187\times256}{6561}. Since $2 …

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