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MISCELLANEOUS EXERCISE - 2 (I) · Q101

Q.Select the correct answer from the given alternatives. The tenth term of H.P. 29,17,219,112,…\dfrac29, \dfrac17, \dfrac2{19}, \dfrac1{12}, \ldots is: A) 127\dfrac1{27} B) 92\dfrac92 C) 52\dfrac52 D) 27

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Reciprocals 92,7,192,12,…\dfrac92,7,\dfrac{19}2,12,\ldots: A.P. with a=4.5,d=2.5a=4.5,d=2.5. t10(A.P.)=4.5+9(2.5)=4.5+22.5=27t_{10}(\text{A.P.})=4.5+9(2.5)=4.5+22.5=27. The H.P. term is the reciprocal of the A.P. term, so $t_{10} …

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