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MISCELLANEOUS EXERCISE - 2 (II) · Q135

Q.Find the coefficient of x6x^6 in the expansion of e2xe^{2x} using series expansion.

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e2x=∑k=0∞(2x)kk!e^{2x}=\sum_{k=0}^\infty\dfrac{(2x)^k}{k!}; the x6x^6 term is 26x66!=64720x6\dfrac{2^6x^6}{6!}=\dfrac{64}{720}x^6. Coefficient: $\df …

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