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MISCELLANEOUS EXERCISE - 2 (II) · Q118

Q.Find 2×5×8+4×7×10+6×9×12+⋯2\times5\times8+4\times7\times10+6\times9\times12+\cdots upto nn terms.

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First factors 2,4,6,…2,4,6,\ldots: tr=2rt_r=2r. Second factors 5,7,9,…5,7,9,\ldots: tr=2r+3t_r=2r+3. Third factors 8,10,12,…8,10,12,\ldots: tr=2r+6t_r=2r+6. Term =2r(2r+3)(2r+6)=8r3+36r2+36r=2r(2r+3)(2r+6)=8r^3+36r^2+36r. $S_n=8\left[\dfrac{n(n+1)}2\right]^2+36\cdot\dfrac{n(n+1)(2n+1)}6+36\cdot\d …

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