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MISCELLANEOUS EXERCISE - 2 (II) · Q122

Q.Find (502−492)+(482−472)+(462−452)+⋯+(22−12)(50^2-49^2)+(48^2-47^2)+(46^2-45^2)+\cdots+(2^2-1^2).

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Pairing (2,1)→r=1(2,1)\to r=1 up to (50,49)→r=25(50,49)\to r=25: (2r)2−(2r−1)2=4r−1(2r)^2-(2r-1)^2=4r-1. Sum $=\sum_{r=1}^{25}(4r-1)=4\cdot\dfrac{2 …

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