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MISCELLANEOUS EXERCISE - 2 (II) · Q112

Q.Find the nnth term of the sequence 0.6,0.66,0.666,0.6666,…0.6, 0.66, 0.666, 0.6666, \ldots

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tn=0.6+0.06+⋯+(n terms)=0.6(1−0.1n)1−0.1=0.60.9(1−0.1n)=23(1−0.1n)t_n=0.6+0.06+\cdots+(n\text{ terms})=\dfrac{0.6(1-0.1^n)}{1-0.1}=\dfrac{0.6}{0.9}(1-0.1^n)=\dfrac23(1-0.1^n). …

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