Q.Find $\displaystyle\sum_{r=1}^{n}\dfrac{2}{3^r}$.

For a G.P. $a, ar, ar^2, \ldots, ar^{n-1}$ with $r\ne1$, the sum of the first $n$ terms is $S_n=\dfrac{a(r^n-1)}{r-1}$, equivalently written $\dfrac{a(1-r^n)}{1-r}$ when $r<1$; this is derived by multiplying $S_n$ by $r$ and subtracting the two series, so every middle term cancels and only a first and a last term survive. When $r=1$, every term equals $a$, so $S_n=na$. A related identity, $S_n-S_{n-1}=t_n$, is useful for recovering the $n$th term when only a formula for $S_n$ is given, and can also be used to …