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Answer the following · Q4

Q.iv. Equilibrium constant of the reaction, 2Cu+(aq)⟶Cu2+(aq)+Cu(s)\mathrm{2Cu^+(aq) \longrightarrow Cu^{2+}(aq) + Cu(s)} is 1.2 ×\times 106^6. What is the standard potential of the cell in which the reaction takes place ? (0.36 V)

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Step 1. For 2Cu+(aq)⇌Cu2+(aq)+Cu(s)2Cu^+(aq)\rightleftharpoons Cu^{2+}(aq)+Cu(s): this is a disproportionation, splitting into Cu++e−→CuCu^++e^-\rightarrow Cu (reduction, cathode) and Cu+→Cu2++e−Cu^+\rightarrow Cu^{2+}+e^- (oxidation, anode), each a 1-electron step, so n=1n=1. …

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