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Question 95 of 111

Q.The standard potential of the cell in the following reaction is _____. Cd(s)+Cu(1M)2+⟶Cd(1M)2++Cu(s)Cd_{(s)} + Cu^{2+}_{(1M)} \longrightarrow Cd^{2+}_{(1M)} + Cu_{(s)} (ECd∘=−0.403VE^\circ_{Cd} = -0.403V, ECu∘=0.334VE^\circ_{Cu} = 0.334V)

(a) –0.737 V
(b) 0.737 V
(c) –0.069 V
(d) 0.069 V
Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2022MCQ· 1mImportance★★★★★
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Cd is oxidised (anode) and Cu²⁺ is reduced (cathode); subtracting their standard potentials gives +0.737 V.

In the reaction Cd(s)+Cu2+(1M)→Cd2+(1M)+Cu(s)Cd(s) + Cu^{2+}(1M) \rightarrow Cd^{2+}(1M) + Cu(s), cadmium is oxidised (anode) and copper(II) ion is reduced (cathode). The standard cell potential is: …

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